# Eulerian Path is a path in graph that visits every edge exactly once.
# Eulerian Circuit is an Eulerian Path which starts and ends on the same
# vertex.
# time complexity is O(V+E)
# space complexity is O(VE)


# using dfs for finding eulerian path traversal
def dfs(u, graph, visited_edge, path=None):
    path = (path or []) + [u]
    for v in graph[u]:
        if visited_edge[u][v] is False:
            visited_edge[u][v], visited_edge[v][u] = True, True
            path = dfs(v, graph, visited_edge, path)
    return path


# for checking in graph has euler path or circuit
def check_circuit_or_path(graph, max_node):
    odd_degree_nodes = 0
    odd_node = -1
    for i in range(max_node):
        if i not in graph.keys():
            continue
        if len(graph[i]) % 2 == 1:
            odd_degree_nodes += 1
            odd_node = i
    if odd_degree_nodes == 0:
        return 1, odd_node
    if odd_degree_nodes == 2:
        return 2, odd_node
    return 3, odd_node


def check_euler(graph, max_node):
    visited_edge = [[False for _ in range(max_node + 1)] for _ in range(max_node + 1)]
    check, odd_node = check_circuit_or_path(graph, max_node)
    if check == 3:
        print("graph is not Eulerian")
        print("no path")
        return
    start_node = 1
    if check == 2:
        start_node = odd_node
        print("graph has a Euler path")
    if check == 1:
        print("graph has a Euler cycle")
    path = dfs(start_node, graph, visited_edge)
    print(path)


def main():
    g1 = {1: [2, 3, 4], 2: [1, 3], 3: [1, 2], 4: [1, 5], 5: [4]}
    g2 = {1: [2, 3, 4, 5], 2: [1, 3], 3: [1, 2], 4: [1, 5], 5: [1, 4]}
    g3 = {1: [2, 3, 4], 2: [1, 3, 4], 3: [1, 2], 4: [1, 2, 5], 5: [4]}
    g4 = {1: [2, 3], 2: [1, 3], 3: [1, 2]}
    g5 = {
        1: [],
        2: []
        # all degree is zero
    }
    max_node = 10
    check_euler(g1, max_node)
    check_euler(g2, max_node)
    check_euler(g3, max_node)
    check_euler(g4, max_node)
    check_euler(g5, max_node)


if __name__ == "__main__":
    main()